<html> <head> <style></style></head> <body class='hmmessage'><div dir='ltr'>Hello I'm having a problem using passing lambda expressions as a parameter in Query filter method.In the following example call to 'findByAge0' works fine, but calling 'findByAge' raises an exception:pony.orm.core.ExprEvalError: age raises NameError: name 'age' is not defined db = Database('sqlite', ':memory:') class Person(db.Entity): name = Required(unicode) age = Required(int) db.generate_mapping(create_tables=True) with db_session: p1 = Person(name="Bing Bang", age=31) p2 = Person(name="Kick Mick", age=75) def findByAge0(age): fn = lambda p: p.age == age q = select(p for p in Person) q = q.filter(fn) with db_session: persons = list(q) for p in persons: print p.name def findByAge(age): fn = lambda p: p.age == age doFindPersons(fn) def doFindPersons(fn): q = select(p for p in Person) q = q.filter(fn) with db_session: persons = list(q) for p in persons: print p.name findByAge0(75) findByAge(75) a = raw_input('[Enter]') Am I doing something wrong or it's not possible to use lambda expression as in this example?Thanks in advance,Tom </div></body> </html>